Solve the Problem $2 \mathrm { ft }$ And Released $\mathrm { s } = \frac { 1 } { 2 } \sin \sqrt { \frac { 1 } { 14 } } \mathrm { t }$

Solve the problem.
-A spring with a spring constant of 7 and a 1-unit mass attached to it is stretched $2 \mathrm { ft }$ and released. What is the equation for the resulting oscillatory motion?

A) $\mathrm { s } = \frac { 1 } { 2 } \sin \sqrt { \frac { 1 } { 14 } } \mathrm { t }$
B) $s = 2 \sin \sqrt { \frac { 1 } { 7 } } t$
C) $s = 2 \sin \sqrt { 7 } t$
D) $s = 7 \sin \sqrt { 2 } t$