Solve.
-The equation $\theta = \cos ^ { - 1 } ( \mathrm { R } / \mathrm { Z } )$ gives the phase angle between $R$ and $Z$ in an $\mathrm { AC }$ circuit. Find $\theta$ if $R = 50$ ohms and $Z = 100$ ohms.
A) $30.0 ^ { \circ }$
B) $60.0 ^ { \circ }$
C) $120.0 ^ { \circ }$
D) $0.7 ^ { \circ }$

Question

Quizplus · Accepted Answer

The phase angle $\theta$ is found by substituting $R = 50$ ohms and $Z = 100$ ohms into the equation $\theta = \cos^{-1}(R/Z)$, resulting in $\theta = \cos^{-1}(50/100) = \cos^{-1}(0.5)$, which equals $60.0^\circ$.

Solve -The Equation θ=cos⁡−1(R/Z)\theta = \cos ^ { - 1 } ( \mathrm { R } / \mathrm { Z } )θ=cos−1(R/Z)

Solve
-The Equation $\theta = \cos ^ { - 1 } ( \mathrm { R } / \mathrm { Z } )$