Determine whether the function is periodic. If it is periodic, find the period.
-$$f ( x ) = x ^ { 2 } \cos 2 x$$
A) $\frac { \pi } { 2 }$
B) Not periodic
C) $2 \pi$
D) $\pi$

Question

Quizplus · Accepted Answer

The function $f(x) = x^2 \cos 2x$ is not periodic because the $x^2$ term does not have a repeating pattern as $x$ changes. The cosine function is periodic, but when multiplied by $x^2$, the overall function loses the periodic nature.

Determine Whether the Function Is Periodic f(x)=x2cos⁡2xf ( x ) = x ^ { 2 } \cos 2 xf(x)=x2cos2x

Determine Whether the Function Is Periodic $f ( x ) = x ^ { 2 } \cos 2 x$