Find the value of the unique real number between 0 and 2 that satisfies the given conditions.
-$\tan \theta = - \frac { \sqrt { 3 } } { 3 }$ and $\cos \theta

Question

Find the value of the unique real number between 0 and 2 that satisfies the given conditions.
-$\tan \theta = - \frac { \sqrt { 3 } } { 3 }$ and $\cos \theta < 0$
A) $\frac { \pi } { 6 }$
B) $\frac { 5 \pi } { 6 }$
C) $\frac { 2 \pi } { 3 }$
D) $\frac { 7 \pi } { 6 }$

Quizplus · Accepted Answer

The angle $\theta$ must be in the second quadrant where $\tan \theta = - \frac{\sqrt{3}}{3}$ and $\cos \theta < 0$. The angle $\frac{5\pi}{6}$ satisfies these conditions.

Find the Value of the Unique Real Number Between 0 tan⁡θ=−33\tan \theta = - \frac { \sqrt { 3 } } { 3 }tanθ=−33​​

Find the Value of the Unique Real Number Between 0 $\tan \theta = - \frac { \sqrt { 3 } } { 3 }$