Evaluate.
-$$\tan \left( \frac { \pi } { 6 } + 2716 \pi \right)$$
A) $\frac { 1 } { 2 }$
B) $\frac { \sqrt { 3 } } { 2 }$
C) $\frac { \sqrt { 3 } } { 3 }$
D) $\sqrt { 3 }$

Question

Quizplus · Accepted Answer

The tangent function has a period of $\pi$. Therefore, $\tan \left( \frac{\pi}{6} + 2716\pi \right) = \tan \left( \frac{\pi}{6} \right)$. The value of $\tan \left( \frac{\pi}{6} \right)$ is $\frac{\sqrt{3}}{3}$.

Evaluate - tan⁡(π6+2716π)\tan \left( \frac { \pi } { 6 } + 2716 \pi \right)tan(6π​+2716π)

Evaluate
- $\tan \left( \frac { \pi } { 6 } + 2716 \pi \right)$