Solve the equation.
-Solve $\sin \theta = \frac { \sqrt { 2 } } { 2 }$ for $\theta$, where $0 ^ { \circ } \leq \theta \leq 90 ^ { \circ }$.
A) $90 ^ { \circ }$
B) $30 ^ { \circ }$
C) $45 ^ { \circ }$
D) $60 ^ { \circ }$

Question

Quizplus · Accepted Answer

The value of $\sin \theta = \frac{\sqrt{2}}{2}$ corresponds to an angle of $45^\circ$ in the first quadrant, where $0^\circ \leq \theta \leq 90^\circ$.

Solve the Equation sin⁡θ=22\sin \theta = \frac { \sqrt { 2 } } { 2 }sinθ=22​​

Solve the Equation $\sin \theta = \frac { \sqrt { 2 } } { 2 }$