Solve the problem.
-The minute hand of a clock is 15 inches long. What distance does its tip move in 27 minutes?
A) $\frac { 3 } { 50 } \pi \mathrm { in }$.
B) $\frac { 3 } { 100 } \pi \mathrm { in }$.
C) $\frac { 27 } { 2 } \pi$ in.
D) $\frac { 27 } { 4 } \pi$ in.

Question

Quizplus · Accepted Answer

The tip of the minute hand describes a circle with a radius of 15 inches. The circumference of this circle is $2\pi r = 2\pi(15) = 30\pi$ inches. In 60 minutes, the tip moves $30\pi$ inches, so in 27 minutes, it moves $\frac{27}{60} \times 30\pi = \frac{27}{2}\pi$ inches.

Solve the Problem 350πin\frac { 3 } { 50 } \pi \mathrm { in }503​πin

Solve the Problem $\frac { 3 } { 50 } \pi \mathrm { in }$