Provide an appropriate response.
-A student claims: "Since $1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta$, I should be able to also say $1 + \cot \theta = \csc \theta$ if I take the square root of both sides." Comment on the student's statement.

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The Answer of Provide an appropriate response.
-A student claims: "Since $1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta$, I should be able to also say $1 + \cot \theta = \csc \theta$ if I take the square root of both sides." Comment on the student's statement.

Provide an Appropriate Response 1+cot⁡2θ=csc⁡2θ1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta1+cot2θ=csc2θ

Provide an Appropriate Response $1 + \cot ^ { 2 } \theta = \csc ^ { 2 } \theta$