Find the area. Round your answer to the nearest hundredth if necessary.
-Find the area of the triangle with the following measurements:
$$\mathrm { B } = 63 ^ { \circ } , \mathrm { a } = 10 \mathrm {~cm} , \mathrm { c } = 22 \mathrm {~cm}$$
A) $98.01 \mathrm {~cm} ^ { 2 }$
B) $196.02 \mathrm {~cm} ^ { 2 }$
C) $49.94 \mathrm {~cm} ^ { 2 }$
D) $110 \mathrm {~cm} ^ { 2 }$

Question

Quizplus · Accepted Answer

The area of a triangle given two sides and an included angle can be found using the formula: $\frac{1}{2}ab\sin(C)$, where $a$ and $b$ are the sides and $C$ is the included angle. Here, we have $a = 10$ cm, $c = 22$ cm, and $B = 63^\circ$. The formula becomes $\frac{1}{2} \times 10 \times 22 \times \sin(63^\circ)$, which calculates to approximately $98.01 \mathrm{cm}^2$.

Find the Area B=63∘,a=10 cm,c=22 cm\mathrm { B } = 63 ^ { \circ } , \mathrm { a } = 10 \mathrm {~cm} , \mathrm { c } = 22 \mathrm {~cm}B=63∘,a=10 cm,c=22 cm

Find the Area $\mathrm { B } = 63 ^ { \circ } , \mathrm { a } = 10 \mathrm {~cm} , \mathrm { c } = 22 \mathrm {~cm}$