Find all solutions in the interval [0, 2π).
-$$\tan \left( \frac { x } { 2 } \right) = \frac { 1 + \cos x } { 1 - \cos x }$$
A) $\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }$
B) $\frac { \pi } { 2 }$
C) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
D) 0

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The Answer of Find all solutions in the interval [0, 2π).
-$$\tan \left( \frac { x } { 2 } \right) = \frac { 1 + \cos x } { 1 - \cos x }$$
A) $\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }$
B) $\frac { \pi } { 2 }$
C) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
D) 0

Find All Solutions in the Interval [0, 2π) tan⁡(x2)=1+cos⁡x1−cos⁡x\tan \left( \frac { x } { 2 } \right) = \frac { 1 + \cos x } { 1 - \cos x }tan(2x​)=1−cosx1+cosx​

Find All Solutions in the Interval [0, 2π) $\tan \left( \frac { x } { 2 } \right) = \frac { 1 + \cos x } { 1 - \cos x }$