Find all solutions in the interval [0, 2π).
-$$\cot \left( \frac { x } { 2 } \right) = \frac { 1 - \cos x } { 1 + \cos x }$$
A) $\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }$
B) 0
C) $\frac { \pi } { 2 }$
D) $\frac { 3 \pi } { 4 } , \frac { 7 \pi } { 4 }$

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The Answer of Find all solutions in the interval [0, 2π).
-$$\cot \left( \frac { x } { 2 } \right) = \frac { 1 - \cos x } { 1 + \cos x }$$
A) $\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }$
B) 0
C) $\frac { \pi } { 2 }$
D) $\frac { 3 \pi } { 4 } , \frac { 7 \pi } { 4 }$

Find All Solutions in the Interval [0, 2π) cot⁡(x2)=1−cos⁡x1+cos⁡x\cot \left( \frac { x } { 2 } \right) = \frac { 1 - \cos x } { 1 + \cos x }cot(2x​)=1+cosx1−cosx​

Find All Solutions in the Interval [0, 2π) $\cot \left( \frac { x } { 2 } \right) = \frac { 1 - \cos x } { 1 + \cos x }$