Rewrite with only sin x and cos x.
-$\sin 3 x - \cos 2 x$
A) $2 \sin x \cos ^ { 2 } x - \sin x + 2 \sin ^ { 3 } x + 1 - 2 \sin ^ { 2 } x$
B) $2 \sin x \cos ^ { 2 } x + \sin x - 2 \sin ^ { 3 } x - 1 - 2 \sin ^ { 2 } x$
C) $2 \sin x \cos ^ { 2 } x + \sin x - 2 \sin ^ { 3 } x - 1 + 2 \sin ^ { 2 } x$
D) $2 \sin x \cos ^ { 2 } x + \sin x - 2 \sin ^ { 2 } x - 1 + 2 \sin ^ { 2 } x$

Question

Quizplus · Accepted Answer

Using the identities:$\sin 3x = 3\sin x - 4\sin^3 x$$\cos 2x = 1 - 2\sin^2 x$$\sin 3x - \cos 2x = 3\sin x - 4\sin^3 x - (1 - 2\sin^2 x)$$\sin 3x - \cos 2x = 3\sin x - 4\sin^3 x - 1 + 2\sin^2 x$$\sin 3x - \cos 2x = 2\sin x \cos^2 x + \sin x - 2\sin^3 x - 1 + 2\sin^2 x$

Rewrite with Only Sin X and Cos X sin⁡3x−cos⁡2x\sin 3 x - \cos 2 xsin3x−cos2x

Rewrite with Only Sin X and Cos X $\sin 3 x - \cos 2 x$