Rewrite with only sin x and cos x.
-$\cos 2 x + \sin x$
A) $1 - 2 \sin ^ { 2 } x + \sin x$
B) $1 + 2 \sin ^ { 2 } x + \sin x$
C) $1 + 3 \sin ^ { 2 } x$
D) $1 + 3 \sin x$

Question

Quizplus · Accepted Answer

The correct expression is obtained by using the double angle formula for cosine, which is $\cos 2x = 1 - 2\sin^2x$. Substituting this into the original expression gives $1 - 2\sin^2x + \sin x$.

Rewrite with Only Sin X and Cos X cos⁡2x+sin⁡x\cos 2 x + \sin xcos2x+sinx

Rewrite with Only Sin X and Cos X $\cos 2 x + \sin x$