Prove the identity.
-$$\frac { \tan t } { 1 - \cot t } + \frac { 1 + \cot t } { \tan t } = \frac { \tan ^ { 2 } t + 2 - \csc ^ { 2 } t } { \tan t - 1 }$$

Name: Prove the identity. -\[\frac { \tan t } { 1 - \cot t } + \frac { 1 + \cot t } { \tan t } = \frac { \tan ^ { 2 } t + 2 - \csc ^ { 2 } t } { \tan t - 1 }\]
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The Answer of Prove the identity.
-$$\frac { \tan t } { 1 - \cot t } + \frac { 1 + \cot t } { \tan t } = \frac { \tan ^ { 2 } t + 2 - \csc ^ { 2 } t } { \tan t - 1 }$$

Prove the Identity tan⁡t1−cot⁡t+1+cot⁡ttan⁡t=tan⁡2t+2−csc⁡2ttan⁡t−1\frac { \tan t } { 1 - \cot t } + \frac { 1 + \cot t } { \tan t } = \frac { \tan ^ { 2 } t + 2 - \csc ^ { 2 } t } { \tan t - 1 }1−cotttant​+tant1+cott​=tant−1tan2t+2−csc2t​

Prove the Identity $\frac { \tan t } { 1 - \cot t } + \frac { 1 + \cot t } { \tan t } = \frac { \tan ^ { 2 } t + 2 - \csc ^ { 2 } t } { \tan t - 1 }$