Find all solutions in the interval [0, 2π]
-$\sin ( \cos x ) = 0$
A) $\frac { \pi } { 2 } , \pi$
B) $0 , \frac { 3 \pi } { 2 }$
C) $\pi , \frac { 3 \pi } { 2 }$
D) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$

Question

Quizplus · Accepted Answer

The equation $\sin(\cos x) = 0$ implies that $\cos x = 0$ or $\cos x = \pi$. However, since $\cos x$ can only take values between -1 and 1, the correct interpretation is that $\cos x = 0$. The values of $x$ in the interval [0, 2π] for which $\cos x = 0$ are $x = \frac{\pi}{2}$ and $x = \frac{3\pi}{2}$.

Find All Solutions in the Interval [0, 2π] - sin⁡(cos⁡x)=0\sin ( \cos x ) = 0sin(cosx)=0

Find All Solutions in the Interval [0, 2π]
- $\sin ( \cos x ) = 0$