Eliminate the parameter.
-$$x = 8 \cos t , y = 8 \sin t$$
A) $( x + y ) ^ { 2 } = 64$
B) $x ^ { 2 } + y ^ { 2 } = 8$
C) $x ^ { 2 } + y ^ { 2 } = 64$
D) $y = x \tan t$

Question

Quizplus · Accepted Answer

Using the Pythagorean identity $\cos^2 t + \sin^2 t = 1$, we substitute $x = 8 \cos t$ and $y = 8 \sin t$ to get $x^2 + y^2 = 64\cos^2 t + 64\sin^2 t = 64(\cos^2 t + \sin^2 t) = 64$.

Eliminate the Parameter x=8cos⁡t,y=8sin⁡tx = 8 \cos t , y = 8 \sin tx=8cost,y=8sint

Eliminate the Parameter $x = 8 \cos t , y = 8 \sin t$