Find the angle between the given vectors to the nearest tenth of a degree.
-$$\mathbf { u } = \left( 3 \cos \frac { \pi } { 6 } \right) \mathbf { i } + \left( 3 \sin \frac { \pi } { 6 } \right) \mathbf { j } , \mathbf { v } = \left( \cos \frac { 4 \pi } { 3 } \right) \mathbf { i } + \left( \sin \frac { 4 \pi } { 3 } \right) \mathbf { j }$$
A) $210 ^ { \circ }$
B) $150 ^ { \circ }$
C) $240 ^ { \circ }$
D) $120 ^ { \circ }$

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The Answer of Find the angle between the given vectors to the nearest tenth of a degree.
-$$\mathbf { u } = \left( 3 \cos \frac { \pi } { 6 } \right) \mathbf { i } + \left( 3 \sin \frac { \pi } { 6 } \right) \mathbf { j } , \mathbf { v } = \left( \cos \frac { 4 \pi } { 3 } \right) \mathbf { i } + \left( \sin \frac { 4 \pi } { 3 } \right) \mathbf { j }$$
A) $210 ^ { \circ }$
B) $150 ^ { \circ }$
C) $240 ^ { \circ }$
D) $120 ^ { \circ }$

Find the Angle Between the Given Vectors to the Nearest