Use the dot product to find $ |\mathbf{v}| $
-$$\mathbf { v } = \langle - 8,3 \rangle$$
A) 11
B) $\sqrt { 73 }$
C) $- 5$
D) $\mathrm { i } \sqrt { 55 }$

Question

Quizplus · Accepted Answer

The magnitude of a vector $\mathbf{v} = \langle a, b \rangle$ is given by $|\mathbf{v}| = \sqrt{a^2 + b^2}$. For $\mathbf{v} = \langle -8, 3 \rangle$, $|\mathbf{v}| = \sqrt{(-8)^2 + 3^2} = \sqrt{64 + 9} = \sqrt{73}$.

Use the Dot Product to Find ∣v∣ |\mathbf{v}| ∣v∣ - v=⟨−8,3⟩\mathbf { v } = \langle - 8,3 \ranglev=⟨−8,3⟩

Use the Dot Product to Find $|\mathbf{v}|$ - $\mathbf { v } = \langle - 8,3 \rangle$