Solve the problem.
-A basketball player shoots the ball with a velocity of $21.5 \mathrm { ft } / \mathrm { s }$ at an angle of $32.4 ^ { \circ }$ with the horizontal. To the nearest tenth, find the magnitude of the horizontal component of the resultant vector.
A) $9.1 \mathrm { ft } / \mathrm { s }$
B) $5.8 \mathrm { ft } / \mathrm { s }$
C) $18.2 \mathrm { ft } / \mathrm { s }$
D) $11.5 \mathrm { ft } / \mathrm { s }$

Question

Quizplus · Accepted Answer

The horizontal component of the velocity is found using $ v_x = v \cdot \cos(\theta) $. Here, $ v = 21.5 \mathrm{ ft/s} $ and $ \theta = 32.4^\circ $. Thus, $ v_x = 21.5 \cdot \cos(32.4^\circ) \approx 18.2 \mathrm{ ft/s} $.

Solve the Problem 21.5ft/s21.5 \mathrm { ft } / \mathrm { s }21.5ft/s

Solve the Problem $21.5 \mathrm { ft } / \mathrm { s }$