Solve the problem.
-Find the maximum value of $\mathrm { f } = 8 \mathrm { x } + 12 \mathrm { y }$ subject to the following constraints.
$$\begin{array} { l }
40 x + 80 y \leq 560 \
6 x + 8 y \leq 72 \
x \geq 0 \
y \geq 0
\end{array}$$
A) Maximum of 92
B) Maximum of 120
C) Maximum of 96
D) Maximum of 100

Question

Solve the problem.
-Find the maximum value of $\mathrm { f } = 8 \mathrm { x } + 12 \mathrm { y }$ subject to the following constraints.
$$\begin{array} { l } 
40 x + 80 y \leq 560 \
6 x + 8 y \leq 72 \
x \geq 0 \
y \geq 0
\end{array}$$
A) Maximum of 92
B) Maximum of 120
C) Maximum of 96
D) Maximum of 100

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Find the maximum value of $\mathrm { f } = 8 \mathrm { x } + 12 \mathrm { y }$ subject to the following constraints.
$$\begin{array} { l } 
40 x + 80 y \leq 560 \
6 x + 8 y \leq 72 \
x \geq 0 \
y \geq 0
\end{array}$$
A) Maximum of 92
B) Maximum of 120
C) Maximum of 96
D) Maximum of 100

Solve the Problem f=8x+12y\mathrm { f } = 8 \mathrm { x } + 12 \mathrm { y }f=8x+12y

Solve the Problem $\mathrm { f } = 8 \mathrm { x } + 12 \mathrm { y }$