Perform the indicated elementary row operations.
-$\begin{array} { l }
( - 10 ) R _ { 2 } + R _ { 1 } \
{ \left[ \begin{array} { r r }
3 & - 1 \
10 & - 3
\end{array} \right] }
\end{array}$

A)$\left[\begin{array}{rr}
-97 & 29 \
10 & -3
\end{array}\right]$

B)$\left[\begin{array}{rr}
3 & -1 \
-100 & 30
\end{array}\right]$

C)$\left[\begin{array}{ll}
13 & -1 \
40 & -3
\end{array}\right]$

D)$\left[\begin{array}{rr}
3 & -1 \
-20 & 7
\end{array}\right]$

Question

Perform the indicated elementary row operations.
-$\begin{array} { l } 
( - 10 ) R _ { 2 } + R _ { 1 } \
{ \left[ \begin{array} { r r } 
3 & - 1 \
10 & - 3
\end{array} \right] }
\end{array}$

A)$\left[\begin{array}{rr}
-97 & 29 \
10 & -3
\end{array}\right]$

B)$\left[\begin{array}{rr}
3 & -1 \
-100 & 30
\end{array}\right]$

C)$\left[\begin{array}{ll}
13 & -1 \
40 & -3
\end{array}\right]$

D)$\left[\begin{array}{rr}
3 & -1 \
-20 & 7
\end{array}\right]$

Quizplus · Accepted Answer

The operation $(-10)R_2 + R_1$ means multiply row 2 by -10 and add it to row 1. For the first element: $(-10)*10 + 3 = -100 + 3 = -97$. For the second element: $(-10)*(-3) - 1 = 30 - 1 = 29$. Row 2 remains unchanged.

Perform the Indicated Elementary Row Operations (−10)R2+R1[3−110−3]\begin{array} { l } ( - 10 ) R _ { 2 } + R _ { 1 } \\{ \left[ \begin{array} { r r } 3 & - 1 \\10 & - 3\end{array} \right] }\end{array}(−10)R2​+R1​[310​−1−3​]​

Perform the Indicated Elementary Row Operations $\begin{array} { l } ( - 10 ) R _ { 2 } + R _ { 1 } \\{ \left[ \begin{array} { r r } 3 & - 1 \\10 & - 3\end{array} \right] }\end{array}$