Match the given graph with its equation.
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A) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$
B) $\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y - 3 ) ^ { 2 } } { 4 } = 1$
C) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y - 3 ) ^ { 2 } } { 16 } = 1$
D) $\frac { ( x - 1 ) ^ { 2 } } { 16 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

Question

Match the given graph with its equation.
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A) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$ 
B) $\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y - 3 ) ^ { 2 } } { 4 } = 1$ 
C) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y - 3 ) ^ { 2 } } { 16 } = 1$ 
D) $\frac { ( x - 1 ) ^ { 2 } } { 16 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

Quizplus · Accepted Answer

The Answer of Match the given graph with its equation.
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A) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$ 
B) $\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y - 3 ) ^ { 2 } } { 4 } = 1$ 
C) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y - 3 ) ^ { 2 } } { 16 } = 1$ 
D) $\frac { ( x - 1 ) ^ { 2 } } { 16 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

Match the Given Graph with Its Equation (x−1)24+(y+3)216=1\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 14(x−1)2​+16(y+3)2​=1

Match the Given Graph with Its Equation $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$