Find the first six terms of the sequence.
-$$a _ { 1 } = 9 , a _ { 2 } = 7 ; \text { for } n \geq 3 , a _ { n } = a _ { n } - 1 - a _ { n - 2 }$$
A) $9,7,2 , - 7 , - 3,8$
B) $9,7,5,3,1 , - 1$
C) $9,7,16,23,36,59$
D) $9,7 , - 2 , - 9 , - 7,2$

Question

Quizplus · Accepted Answer

The sequence is defined recursively. Starting with $a_1 = 9$ and $a_2 = 7$, we calculate subsequent terms using the formula $a_n = a_{n-1} - a_{n-2}$. This gives $a_3 = 7 - 9 = -2$, $a_4 = -2 - 7 = -9$, $a_5 = -9 - (-2) = -7$, and $a_6 = -7 - (-9) = 2$.

Find the First Six Terms of the Sequence a1=9,a2=7; for n≥3,an=an−1−an−2a _ { 1 } = 9 , a _ { 2 } = 7 ; \text { for } n \geq 3 , a _ { n } = a _ { n } - 1 - a _ { n - 2 }a1​=9,a2​=7; for n≥3,an​=an​−1−an−2​

Find the First Six Terms of the Sequence $a _ { 1 } = 9 , a _ { 2 } = 7 ; \text { for } n \geq 3 , a _ { n } = a _ { n } - 1 - a _ { n - 2 }$