Solve the problem.
-A rectangular enclosure must have an area of at least $3200 \mathrm { yd } 2$. If $240 \mathrm { yd }$ of fencing is to be used, and the width cannot exceed the length, within what limits must the width of the enclosure lie?
A) $0 \leq w \leq 40$
B) $40 \leq w \leq 80$
C) $60 \leq w \leq 80$
D) $40 \leq w \leq 60$

Question

Quizplus · Accepted Answer

The perimeter constraint is $2l + 2w = 240$, simplifying to $l + w = 120$. The area constraint is $lw \geq 3200$. Solving these inequalities gives $40 \leq w \leq 60$.

Solve the Problem 3200yd23200 \mathrm { yd } 23200yd2 If 240yd240 \mathrm { yd }240yd

Solve the Problem $3200 \mathrm { yd } 2$ If $240 \mathrm { yd }$