Solve the problem.
-A projectile is thrown upward so that its distance above the ground after t seconds is h = -11t2 + 286t. After how many seconds does it reach its maximum height?
A) 19.5 s
B) 13 s
C) 26 s
D) 6 s

Question

Quizplus · Accepted Answer

The maximum height of a projectile is reached at the vertex of the parabola described by the quadratic equation h = -11t^2 + 286t. The time at which the maximum height is reached can be found using the formula t = -b/(2a) for the vertex of a parabola, where a = -11 and b = 286. Substituting these values gives t = -286/(2 * -11) = 13 seconds.

Solve the Problem. -A Projectile Is Thrown Upward So That Its Distance Above