Solve the equation using the quadratic formula.
-$$x ^ { 2 } - 6 x + 3 = 0$$
A) $x = - 3 - \sqrt { 6 }$ or $x = - 3 + \sqrt { 6 }$
B) $x = 3 - \sqrt { 12 }$ or $x = 3 + \sqrt { 12 }$
C) $x = 3 - \sqrt { 6 }$ or $x = 3 + \sqrt { 6 }$
D) $x = 3$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For the equation $x^2 - 6x + 3 = 0$, $a = 1$, $b = -6$, and $c = 3$. Plugging these into the formula gives $x = \frac{6 \pm \sqrt{36 - 12}}{2} = \frac{6 \pm \sqrt{24}}{2} = \frac{6 \pm 2\sqrt{6}}{2} = 3 \pm \sqrt{6}$.

Solve the Equation Using the Quadratic Formula x2−6x+3=0x ^ { 2 } - 6 x + 3 = 0x2−6x+3=0

Solve the Equation Using the Quadratic Formula $x ^ { 2 } - 6 x + 3 = 0$