Find which values of x are solutions.
-$\sqrt { 16 - x ^ { 2 } } + 2 = 6$
a. $x = 4$
b. $x = - 4$
c. $x = 0$
A) (a) and (c)
B) (a) and (b)
C) (b)
D) (c)

Name: Find which values of x are solutions. -$\sqrt { 16 - x ^ { 2 } } + 2 = 6$ a. $x = 4$ b. $x = - 4$ c. $x = 0$ A) (a) and (c) B) (a) and (b) C) (b) D) (c)
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The Answer of Find which values of x are solutions.
-$\sqrt { 16 - x ^ { 2 } } + 2 = 6$
a. $x = 4$
b. $x = - 4$
c. $x = 0$
A) (a) and (c)
B) (a) and (b)
C) (b)
D) (c)

Find Which Values of X Are Solutions 16−x2+2=6\sqrt { 16 - x ^ { 2 } } + 2 = 616−x2​+2=6

Find Which Values of X Are Solutions $\sqrt { 16 - x ^ { 2 } } + 2 = 6$