Find the standard form equation for the circle.
-Center $( - 1,2 )$, radius $\sqrt { 2 }$
A) $( x - 1 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 2$
B) $( x + 1 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 2$
C) $( x + 2 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 4$
D) $( x - 2 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 4$

Question

Quizplus · Accepted Answer

The standard form equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center of the circle and $r$ is the radius. Given the center $(-1, 2)$ and radius $\sqrt{2}$, the equation becomes $(x + 1)^2 + (y - 2)^2 = (\sqrt{2})^2$ or $(x + 1)^2 + (y - 2)^2 = 2$, which matches option B.

Find the Standard Form Equation for the Circle (−1,2)( - 1,2 )(−1,2)

Find the Standard Form Equation for the Circle $( - 1,2 )$