In a Hardy-Weinberg population with two alleles A1 and A2 that are in equilibrium, the frequency of the allele A2 is 0.3. What is the frequency of individuals that are homozygous for this allele?
A) 0.09
B) 0.49
C) 0.9
D) 9.0

Question

Quizplus · Accepted Answer

The frequency of individuals homozygous for the allele A2 (A2A2) can be calculated using the Hardy-Weinberg principle as p^2, q^2, or 2pq for different genotypes, where p and q represent the frequencies of the two alleles, and p + q = 1. Given that the frequency of A2 is 0.3 (q = 0.3), the frequency of homozygous A2A2 individuals is q^2 = 0.3^2 = 0.09.

In a Hardy-Weinberg Population with Two Alleles A1 and A2