If a doubly-ionized oxygen atom (O^-²)is accelerated from rest by going through a potential difference of 20 V,what will be the change in its kinetic energy? A)10 eV B)20 eV C)40 eV D)none of the above

Question

Quizplus · Accepted Answer

The change in kinetic energy of a doubly-ionized oxygen atom can be calculated using the formula:
ΔK = qΔV
where 
ΔK = change in kinetic energy 
q = charge of the particle 
ΔV = potential difference

Here, the charge of the particle is 2e (since it is a doubly-ionized oxygen atom), and the potential difference is 20 V. 
ΔK = 2e x 20 V 
ΔK = 40 eV

Therefore, the change in kinetic energy of the doubly-ionized oxygen atom will be 40 eV. Option C is the correct answer.

If a Doubly-Ionized Oxygen Atom (O-2)is Accelerated from Rest by Going

If a Doubly-Ionized Oxygen Atom (O^-²)is Accelerated from Rest by Going