Light in air enters a diamond (n = 2.42)at an angle of incidence of 48.0 $\degree$.What is the angle of refraction inside the diamond?
A)17.9 $\degree$
B)19.8 $\degree$
C)24.7 $\degree$
D)45.6 $\degree$

Question

Quizplus · Accepted Answer

Using Snell's Law, we have:

n1sinθ1 = n2sinθ2

where n1 is the refractive index of the air (approximately 1), θ1 is the angle of incidence, n2 is the refractive index of the diamond (2.42), and θ2 is the angle of refraction.

Plugging in the given values, we have:

1sin48.0 = 2.42sinθ2

Solving for θ2, we get:

θ2 = sin⁻¹(1sin48.0/2.42) = 17.9°

Therefore, the answer is A) 17.9°.

Light in Air Enters a Diamond (N = 2 °\degree° What Is the Angle of Refraction Inside the Diamond? A)17

Light in Air Enters a Diamond (N = 2 $\degree$ What Is the Angle of Refraction Inside the Diamond?
A)17