Consider an escalator at an angle of 45° above the horizontal that moves with a velocity of 2.0 m/s. The vertical component of its velocity is about
A)0)7 m/s.
B)1)4 m/s.
C)1)6 m/s.
D)2)0 m/s.

Question

Quizplus · Accepted Answer

The vertical component of the velocity can be found using the sine of the angle: v_vertical = v_total * sin(45°). Since sin(45°) = √2/2 ≈ 0.707, the vertical component is 2.0 m/s * 0.707 ≈ 1.4 m/s.

Consider an Escalator at an Angle of 45° Above the Horizontal