What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon according to the following chemical equation? Al₂O₃ + 3C → 2Al + 3CO A) 15.9 g B) 31.8 g C) 44.9 g D) 63.6 g E) 67.4 g

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The theoretical yield of aluminum can be calculated using stoichiometry. First, determine the molar mass of aluminum oxide (Al2O3) which is 101.96 g/mol and the molar mass of aluminum (Al) which is 26.98 g/mol. Next, calculate the moles of aluminum oxide and carbon present. For aluminum oxide: 60.0 g / 101.96 g/mol = 0.588 mol. The balanced equation shows that 2 moles of aluminum are produced for every mole of aluminum oxide reacted. Therefore, the moles of aluminum produced are 2 * 0.588 mol = 1.176 mol. The mass of aluminum produced is then 1.176 mol * 26.98 g/mol = 31.7 g, which rounds to 31.8 g, making option B the correct answer.

What Is the Theoretical Yield of Aluminum That Can Be