If 13.9 g of oxygen react with 33.7 g of calcium to produce calcium oxide, what is the limiting reactant and what mass of calcium oxide is produced?
A) Calcium is the limiting reactant and 47.2 g of calcium oxide are produced.
B) Oxygen is the limiting reactant and 24.4 g of calcium oxide are produced.
C) Calcium is the limiting reactant and 60.6 g of calcium oxide are produced.
D) Oxygen is the limiting reactant and 48.7 g of calcium oxide are produced.
E) Calcium is the limiting reactant and 23.6 g of calcium oxide are produced.

Question

Quizplus · Accepted Answer

The balanced chemical equation is:2Ca + O2 → 2CaOMoles of Ca = 33.7 g / 40.08 g/mol = 0.841 molMoles of O2 = 13.9 g / 32.00 g/mol = 0.434 molThe mole ratio of Ca to O2 is 2:1, so the limiting reactant is O2.Moles of CaO produced = 0.434 mol O2 × (2 mol CaO / 1 mol O2) = 0.868 molMass of CaO produced = 0.868 mol × 56.08 g/mol = 48.7 g

If 139 G of Oxygen React with 33