The enthalpy of combustion of acetylene (C₂H₂) is described by
C₂H₂(g) + 5/2O₂(g) → 2CO₂(g) + H₂O(l) ΔH°_rxn= -1299 kJ/mol
Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation: ΔH°_f(CO₂(g)) = -393.5 kJ/mol; ΔH°_f(H₂O(l)) = -285.8 kJ/mol

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The Answer of The enthalpy of combustion of acetylene (C₂H₂) is described by C₂H₂(g) + 5/2O₂(g) → 2CO₂(g) + H₂O(l) ΔH°_rxn= -1299 kJ/mol Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation: ΔH°_f(CO₂(g)) = -393.5 kJ/mol; ΔH°_f(H₂O(l)) = -285.8 kJ/mol

The Enthalpy of Combustion of Acetylene (C2H2) Is Described by

The Enthalpy of Combustion of Acetylene (C₂H₂) Is Described by