How much heat is evolved if 0.600 kg of SO₂ is burned in excess oxygen? 2SO₂(g) + O₂(g) → 2SO₃(g) ΔH°_rxn= -198 kJ/mol A) 5.46 × 10^-2 kJ B) 927 kJ C) 1.85 × 10³ kJ D) 59,400 kJ E) 3.71 × 10³ kJ

Question

Quizplus · Accepted Answer

Given the reaction and its ΔH°_rxn value, we can calculate the heat evolved by first determining the number of moles of SOS (assuming SOS represents the compound in question) burned, and then applying the given ΔH°_rxn value. The molar mass of SOS is not directly provided, but assuming "SOS" is a placeholder for a real compound, we would use its molar mass to convert from kilograms to moles. Since the question does not specify the molar mass, we proceed with the given information that 0.600 kg of SOS is burned and the reaction releases -198 kJ/mol. The calculation would involve converting the mass of SOS to moles (which we can't do precisely without the molar mass) and then using the stoichiometry of the reaction and the ΔH°_rxn value to find the total heat evolved. Without the exact molar mass of SOS, we cannot perform a detailed calculation, but the correct answer would be based on understanding that the heat evolved is directly related to the amount of substance reacted and the enthalpy change of the reaction. Since option B is the only one that seems reasonable and specific numerical calculation details are not provided, it is selected based on the assumption that it aligns with a typical calculation for the given mass and ΔH°_rxn.

How Much Heat Is Evolved If 0