If 75.4 J of energy is absorbed by 0.25 mol of CCl₄ at constant pressure, what is the change in temperature? The specific heat of CCl₄ is 0.861 J/g·°C. A) 17.8°C B) 21.9°C C) 2.3°C D) 9.1°C E) 44.6°C

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Quizplus · Accepted Answer

To find the change in temperature, use the formula q = m*c*ΔT. First, calculate the mass of 0.25 mol of CCl4: (0.25 mol) * (153.82 g/mol) = 38.455 g. Then, rearrange the formula to find ΔT: ΔT = q / (m*c) = 75.4 J / (38.455 g * 0.861 J/g°C) = 2.3°C.

If 754 J of Energy Is Absorbed by 0