What volume of chlorine gas at 25°C and 0.950 atm can be produced by the reaction of 12.0 g of MnO₂ in excess HCl(aq) ? MnO₂(s) + 4HCl(aq) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
(R = 0.08206 L • atm/K • mol)

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The Answer of What volume of chlorine gas at 25°C and 0.950 atm can be produced by the reaction of 12.0 g of MnO₂ in excess HCl(aq)? MnO₂(s) + 4HCl(aq) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g) (R = 0.08206 L • atm/K • mol) A) 5.36 × 10^-3 L B) 0.138 L C) 0.282 L D) 3.09 L E) 3.55 L

What Volume of Chlorine Gas at 25°C and 0