What is the density of SF₆(g) at 27°C and 0.500 atm pressure? (R = 0.08206 L • atm/K • mol) A) 3.38 × 10^-3 g/L B) 2.97 g/L C) 22.4 g/L D) 32.9 g/L E) 3.38 kg/L

Question

Quizplus · Accepted Answer

The density of a gas can be calculated using the formula: density = (P * M) / (R * T), where P is pressure, M is molar mass, R is the gas constant, and T is temperature in Kelvin. For SF6, M = 146.06 g/mol, P = 0.500 atm, T = 300 K (27°C + 273), and R = 0.08206 L•atm/K•mol. Plugging in these values gives a density of approximately 2.97 g/L.

What Is the Density of SF6(g) at 27°C and 0

What Is the Density of SF₆(g) at 27°C and 0