What is the percent CsCl by mass in a 0.711 M aqueous CsCl solution that has a density of 1.091 g/mL? A) 1.53% B) 3.87 × 10^-1% C) 11.0% D) 12.0% E) 65.2%

Question

Quizplus · Accepted Answer

First, we need to calculate the molarity of CsCl in the solution:

Molarity = moles of solute / liters of solution

0.711 M means there are 0.711 moles of CsCl in 1 liter of solution.

Next, we need to calculate the mass of CsCl in 1 liter of solution:

Mass = molarity x molar mass

The molar mass of CsCl is 168.36 g/mol.

Mass = 0.711 x 168.36 = 119.64 g

Finally, we need to calculate the mass percent of CsCl in the solution:

Mass percent = (mass of CsCl / mass of solution) x 100%

The density of the solution is 1.091 g/mL, so 1 liter of solution has a mass of 1.091 kg.

Mass percent = (119.64 g / 1.091 kg) x 100% = 10.97%

Therefore, the percent CsCl by mass in the solution is 10.97%, which is closest to answer choice C (11.0%).

What Is the Percent CsCl by Mass in a 0