Cyclopropane is converted to propene in a first-order process. The rate constant is 5.4 × 10^-2 h^-1. If the initial concentration of cyclopropane is 0.150 M, what will its concentration be after 22.0 hours? A) 0.046 M B) 0.11 M C) 0.13 M D) 0.49 M E) 0.054 M

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The integrated rate law for a first-order reaction is:ln[A]t = -kt + ln[A]0where [A]t is the concentration of the reactant at time t, k is the rate constant, and [A]0 is the initial concentration of the reactant.Substituting the given values into the integrated rate law, we get:ln[0.150 M] = -(5.4 × 10^-2 h^-1)(22.0 h) + ln[A]0Solving for [A]t, we get:[A]t = 0.046 MTherefore, the concentration of cyclopropane after 22.0 hours will be 0.046 M.

Cyclopropane Is Converted to Propene in a First-Order Process