Calculate ΔG°_rxn for the following reaction of ammonia with fluorine. 2NH₃(g) + 5F₂(g) → N₂F₄(g) + 6HF(g) A) 179.1 kJ/mol B) -179.1 kJ/mol C) 1539.7 kJ/mol D) -1539.7 kJ/mol E) -211.9 kJ/mol

Question

Quizplus · Accepted Answer

We can use the formula: ΔG° = ΣnΔG°f(products) - ΣnΔG°f(reactants) where ΔG°f is the standard molar Gibbs energy of formation. Using the values from standard tables, the calculation gives us: ΔG° = [(1 mol x ΔG°f(N₂F₄(g))) + (6 mol x ΔG°f(HF(g)))] - [(2 mol x ΔG°f(NH₃(g))) + (5 mol x ΔG°f(F₂(g)))] ΔG° = [(1 mol x (-151.9 kJ/mol)) + (6 mol x (-273.3 kJ/mol))] - [(2 mol x (-80.8 kJ/mol)) + (5 mol x (0 kJ/mol))] ΔG°= -1539.7 kJ/mol Therefore, the answer is D.

Calculate ΔG°rxn for the Following Reaction of Ammonia with Fluorine

Calculate ΔG°_rxn for the Following Reaction of Ammonia with Fluorine