If we conduct a poll of 1600 people, then what is the approximate margin of error for a 95% confidence interval?
A)2.5%
B)2.8%
C)3.1%
D)3.4%

Question

Quizplus · Accepted Answer

The margin of error for a 95% confidence interval can be calculated using the formula $ME = Z \times \sqrt{\frac{p(1-p)}{n}}$, where $Z$ is the Z-score for the desired confidence level (approximately 1.96 for 95%), $p$ is the proportion (assuming 0.5 for maximum variability), and $n$ is the sample size. Plugging in the values, $ME = 1.96 \times \sqrt{\frac{0.5 \times 0.5}{1600}} \approx 0.0245$ or 2.5%.

If We Conduct a Poll of 1600 People, Then What