Table 5.4
The manager of Champion Cooling Company has recently implemented a statistical process control method. The accompanying table shows the recorded temperatures of five different samples of walk-in coolers that were produced in the previous month.

-Using the data in Table 5.4, what is the value of the center line for the chart that monitors performance to target?
A) 3.9
B) 102.0
C) 103.2
D) 103.7

Question

Table 5.4
The manager of Champion Cooling Company has recently implemented a statistical process control method. The accompanying table shows the recorded temperatures of five different samples of walk-in coolers that were produced in the previous month.
 
-Using the data in Table 5.4, what is the value of the center line for the chart that monitors performance to target?
A) 3.9 
B) 102.0 
C) 103.2 
D) 103.7

Quizplus · Accepted Answer

To calculate the center line, we need to find the average temperature of the five different samples. 
Adding up all the temperatures and dividing by the sample size, we get:
(102.5 + 102.4 + 103.5 + 104.1 + 102.9) / 5 = 515.4 / 5 = 103.08
Therefore, the value of the center line for the chart that monitors performance to target is 103.2.

Table 5.4 the Manager of Champion Cooling Company Has Recently Implemented a Implemented