Constant acceleration: A car starts from rest and accelerates with a constant acceleration of 1.00 m/s² for 3.00 s. The car continues for 5.00 s at constant velocity. How far has the car traveled from its starting point? A) 24.0 m B) 9.00 m C) 19.5 m D) 4.50 m E) 15.0 m

Question

Quizplus · Accepted Answer

The distance traveled during the acceleration phase can be found using the equation d = 1/2 * a * t^2, where d is distance, a is acceleration, and t is time. Plugging in the values given, we get d = 1/2 * 1.00 m/s^2 * (3.00 s)^2 = 4.50 m.

During the constant velocity phase, the distance traveled can be found using the equation d = v * t, where v is velocity and t is time. Since the car is traveling at a constant velocity, we can use the velocity it reaches at the end of the acceleration phase, which is 3.00 m/s (since acceleration is constant). Plugging in the values, we get d = 3.00 m/s * 5.00 s = 15.0 m.

Adding the distances together, we get a total distance of 4.50 m + 15.0 m = 19.5 m, which corresponds to choice C.

Constant Acceleration: a Car Starts from Rest and Accelerates with a Constant