At sea level, at a latitude where , a pendulum that takes 2.00 s for a complete swing back and forth has a length of 0.993 m. What is the value of g in m/s² at a location where the length of such a pendulum is 0.970 m? A) 0.098 3 B) 3.05 C) 9.57 D) 10.0 E) 38.3

Question

Quizplus · Accepted Answer

Using the equation T=2π√(L/g), we can solve for g at sea level: 
2.00=sqrt[(0.993)/g] * 2π 
g=9.81 m/s^2

We can then use this value of g to solve for the period of the pendulum at the new location: 
T=2π√(L/g) 
T=2π√(0.970/9.81) 
T=1.97 s

Finally, we can use this period to solve for the value of g at the new location: 
1.97=sqrt[(0.970)/g] * 2π 
g=9.57 m/s^2

Therefore, the answer is C.

At Sea Level, at a Latitude Where , a Pendulum