Charge of uniform density (40 pC/m²) is distributed on a spherical surface (radius = 1.0 cm), and a second concentric spherical surface (radius = 3.0 cm) carries a uniform charge density of 60 pC/m². What is the magnitude of the electric field at a point 2.0 cm from the center of the two surfaces? A) 1.1 N/C B) 4.5 N/C C) 1.4 N/C D) 5.6 N/C E) 0.50 N/C

Question

Quizplus · Accepted Answer

The electric field at 2.0 cm is due to the charge on the inner sphere only, as the point is inside the outer sphere. Using Gauss's law, E = (σ/ε₀) * (r/R) where σ is the surface charge density of the inner sphere, ε₀ is the permittivity of free space, r is the distance from the center, and R is the radius of the inner sphere. Substituting the given values, E = (40 pC/m²) / (8.85 x 10⁻¹² C²/N·m²) * (2 cm / 1 cm) = 1.1 N/C.

Charge of Uniform Density (40 PC/m2) Is Distributed on a Spherical

Charge of Uniform Density (40 PC/m²) Is Distributed on a Spherical