Approximately how much uranium (in kg) must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%) . The nuclear reaction is . m(n) = 1.008 665 u
M(U) = 235.043 915 u
M(Ba) = 140.913 9 u
M(Kr) = 91.897 3 u
U = 1.66 × 10−²⁷ kg

Question

Approximately how much uranium (in kg) must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%) . The nuclear reaction is

. m(n) = 1.008 665 u
M(U) = 235.043 915 u
M(Ba) = 140.913 9 u
M(Kr) = 91.897 3 u
U = 1.66 × 10−²⁷ kg

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The Answer of Approximately how much uranium (in kg) must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%). The nuclear reaction is . m(n) = 1.008 665 u M(U) = 235.043 915 u M(Ba) = 140.913 9 u M(Kr) = 91.897 3 u U = 1.66 × 10−²⁷ kg A) 1.0 B) 3.5 C) 2.3 D) 4.6 E) 0.1

Approximately How Much Uranium (In Kg) Must Undergo Fission Per