An 8.0-kg object rests on the floor of an elevator which is accelerating downward at a rate of 1.3 m/s². What is the magnitude of the force the object exerts on the floor of the elevator? A) 59 N B) 10 N C) 89 N D) 68 N E) 78 N

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Quizplus · Accepted Answer

The force exerted by the object on the floor of the elevator can be calculated using the formula $F = ma$, where $m$ is the mass of the object and $a$ is the acceleration. However, since the elevator is accelerating downward, the effective acceleration acting on the object is $g - a$, where $g = 9.8 \, \text{m/s}^2$ is the acceleration due to gravity and $a = 1.3 \, \text{m/s}^2$ is the acceleration of the elevator. Thus, the effective acceleration is $9.8 - 1.3 = 8.5 \, \text{m/s}^2$. The force exerted by the object is then $F = 8.0 \, \text{kg} \times 8.5 \, \text{m/s}^2 = 68 \, \text{N}$.

An 80-Kg Object Rests on the Floor of an Elevator Which