What is the de Broglie wavelength of an electron traveling at a velocity of 4.53 × 10⁶ m/s in a hydrogen atom? Given: Mass of an electron: 9.11 × 10^-31 kilograms A) 2.26 × 10^-34m B) 9.10 × 10^-31m C) 4.78 × 10^-11m D) 6.74 × 10^-14m E) 1.61 × 10^-10m

Question

Quizplus · Accepted Answer

The de Broglie wavelength (λ) of an electron can be calculated using the formula λ = h/p, where h is Planck's constant (6.626 × 10^-34 m^2 kg/s) and p is the momentum of the electron. Momentum (p) can be calculated using the formula p = mv, where m is the mass of the electron and v is its velocity.

Substituting the given values, we get:
p = (9.11 × 10^-31 kg)(4.53 × 10^6 m/s) = 4.13 × 10^-24 kg m/s
λ = (6.626 × 10^-34 m^2 kg/s)/(4.13 × 10^-24 kg m/s) = 1.61 × 10^-10 m

Therefore, the answer is E) 1.61 × 10^-10 m.

What Is the De Broglie Wavelength of an Electron Traveling